The 2019 South American U-17 Championship (
Spanish: Campeonato Sudamericano Sub-17 Perú 2019,
Brazilian Portuguese: Campeonato Sul-Americano Sub-17 Peru 2019) was the 18th edition of the
South American U-17 Championship, the biennial international youth
football championship organised by
CONMEBOL for the men's under-17 national teams of South America. It was held in
Peru from 21 March to 14 April 2019.[1]
The top four teams, champions
Argentina, which won their fourth title,
Chile,
Paraguay, and
Ecuador, qualified for the
2019 FIFA U-17 World Cup in
Brazil as the CONMEBOL representatives, besides
Brazil who qualified automatically as hosts replacing
Peru, despite failing to qualify out of the first stage as defending champions for the first time.[2]
Teams
All ten
CONMEBOL member national teams entered the tournament.
Players born on or after 1 January 2002 are eligible to compete. Each team can register a squad of 23 players (three of whom must be goalkeepers).
Draw
The draw of the tournament was held on 27 February 2019, 12:00
PET (
UTC−5), at the Peruvian Football Federation headquarters in
Lima,
Peru.[4] The ten teams were drawn into two groups of five. The host Peru and the defending champions Brazil were seeded into Group A and Group B respectively and assigned to position 1 in their group, while the remaining eight teams were placed into four "pairing pots" according to their final positions in the
2017 South American U-17 Championship (shown in brackets).[5]