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"[…] Second, when they asked how many seconds a man has lived who is 70 years, 17 days and 12 hours old, he answered in a minute and a half 2,210,500,800. One of the men was working out the problems on paper, and informed Fuller that he was wrong, because the answer was much smaller. Fuller hastily replied, "'Top, massa, you forget de leap year." When the leap year was added in, the sums matched.[3] […]"
The information above is in correct 70 years, 17 days and 12 hours old, ≠ 2,210,500,800. but = to [70(365x24h+6h)+(17x24h)+ 12]60²= 2 210 544 000
Note this is only correct for 70 years, 17 days = 2,210,500,800.
check this [70(365x24h+6h)+(17x24h)]60²= 2 210 500 800
note 70 years multiply by (356 days in a year multiply by 24 hours of a day plus 6 hour for leap year as it is a 1/4 day) then + 17 days multiply by 24 hours of a day + 12 hours all multiplied by 60 minutes x 60 seconds. — Preceding unsigned comment added by Udjat ( talk • contribs) 18:43, 8 April 2017 (UTC)
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— Assignment last updated by Lostparti ( talk) 04:28, 23 February 2023 (UTC)