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I'm not an expert, or even a physicist, but (as I understand it) the values describe the chances of a gluon having the combination of those 'colors' (they're not really colors, just convenient labels). If you want the chances of the combination to come out between zero and one (that's required) you have to
normalize them. Hence you device by the sqrt(1^2+1^2+1^2)=sqrt(3). It's basically the Pythagorean theorem in disguise. Ask an actual physicist for a better answer.
Kleuske (
talk)
10:15, 21 October 2021 (UTC)reply
The value of the color charge is a
complexunit vector in a three-dimensional complex vector space (a complex three-dimensional
Hilbert space). The
eigenvectors that span the space is the three colors of the color charge (i.e. the basis axes X, Y, Z of this space are labeled "red", "green", "blue", or in physics-speak where the is called a "ket", from the
bra-ket notation.) These color charge vectors define the probabilities for
measurement of the color charge. The sqrt(3) term is for normalization the quantum state, so it remains a unit vector (see
unitarity). The 1/sqrt(3) factor is the
probability amplitude of each of the possible outcomes of this three-level
quantum state. · · ·
Omnissiahs hierophant (
talk)
18:57, 16 December 2021 (UTC)reply
Interaction with gravity?
Why don't we list gravity under "Interactions" in the infobox? Or maybe more precisely, why do we list gravity as an interaction for some particles (for example
quarks and
photons) but not for all particles? I thought all particles were affected by gravity in the sense that all of them follow
geodesics, and that all particles had a gravitational effect on other particles, since all particles have an energy and energy curves space, which gives rise to orbits that look like they are affected by gravity. —
Kri (
talk)
17:58, 16 December 2021 (UTC)reply
Maybe no one has seen a gluon interact with gravity. No experimental data. We should avoid making stuff up just because it makes sense. What if gluons don't interact with gravity? — Preceding
unsigned comment added by
98.128.172.242 (
talk)
12:01, 17 December 2021 (UTC)reply
while the following appear to be particle/antiparticle pairs:
red–antigreen (), green–antired ()
red–antiblue (), blue–antired ()
green–antiblue (), blue–antigreen ()
Is that a correct interpretation? If that's the case for the particle/antiparticle pairs above, then that would be a case of bosons having antiparticles (or is it only fermions that could have antiparticles?)!
137.82.118.58 (
talk)
00:13, 9 June 2023 (UTC)reply
article level not appropriate for general encylopedia
wiki is supposed to be a general encyclopedia, accessible to the average person
I don't know what the average person is, but this article is written at way too high a level, it’s more appropriate for a college senior majoring on physics — Preceding
unsigned comment added by
50.245.17.105 (
talk)
20:38, 1 November 2023 (UTC)reply