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Archive 1 |
I think the mention of the 1-farad capacitors for 1000W car-stereos is rather non-encyclopedic. And what is meant by "sufficient to drive"? Do these capacitors generate power? I suspect that the real answer is that by trial-and-error, someone has figured out that 1F capacitors can be used to stabilize the cars electrical system while playing typical (loud) music. That is, during the most powerful bass-bursts, the capacitor can feed current to the amplifier, and then be recharged until the next beat comes.
I have added a picture of a 1F capacitor. If it is preferable to the existing one, maybe the existing one can be removed. — 128.171.10.147 ( talk) 02:50, 27 September 2007 (UTC)
How does Image:Supercaps_1.5F_capacitors.jpg swing you? They are 1.5F, not 1F, though. - Keith D. Tyler ¶ ( AMA) 19:37, 26 January 2007 (UTC)
I'm not sure why the definition with equivalent units was removed a few days ago without a descriptive comment or Talk entry. I think this is necessary and useful information, and it is included in similar articles, such as Volt. I added it back with some tweaks. Edurant 05:44, 14 March 2007 (UTC)
The description on the second picture which has the words "tricked-out car," has to be unnecessary. Re-wording it with "...fills the back seat of a car." Under most situations, people know that stock cars don't normally have large capacitors for a stock stereo (i.e. custom stereo systems = custom parts, stock stereo = stock parts). -- Specter01010 02:53, 19 April 2007 (UTC)
That looks VERY small for a 1F capacitor 86.29.81.44 ( talk) 07:04, 16 April 2008 (UTC)
Corrected the "Faraday" link from http://en.wikipedia.org/wiki/Faraday to http://en.wikipedia.org/wiki/Faraday_(unit) 77.127.68.216 ( talk) 20:13, 24 June 2008 (UTC)
One coulomb of charge is 6.25e18 (6.25 * 10^18, or 6.25 billion billion) electrons. One amp represents a rate of electron flow of 1 coulomb of electrons per second, so a 1-farad capacitor can hold 1 amp-second of electrons at 1 volt.
SMalken 18 August 2008 202.1.53.80 00:26, 18 August 2008 (UTC)
17-Sep-2008: I have added subheaders above as "Topics from 2005" (etc.) to emphasize the dates of topics in the talk-page. Older topics might still apply, but using the year headers helps to focus on more current issues. Also, new topics might be more readily added to the bottom, not top. Afterward, I sorted older topics into date order. - Wikid77 ( talk) 05:04, 17 September 2008 (UTC)
17-Sep-2008: I have been revising several articles tagged as "too technical" to focus for general readers. The term "microfarad" is very common, so I repeated it in the top paragraph, according to the Wikipedia style of including redirection terms in the top text, to reassure readers that their topic is covered by the article. For simplicity, it is good to mention the subtopics (such as "microfarad") near the top, so the reader doesn't see a " shaggy dog story" before their specific issue is addressed in the article. However, to off-load details, I inserted the phrase "(defined below)" to alert the reader to continued reading, without cluttering the top text with those sub-details. It is a balancing act: to mention sub-topics briefly in the top text, but then defer the actual sub-details until further in the article. - Wikid77 ( talk) 05:18, 17 September 2008 (UTC)
I added the conversion from power, time and voltage. I needed this to work out regen braking so I thought I'd add it too. —Preceding unsigned comment added by 81.174.174.31 ( talk) 22:56, 3 March 2010 (UTC)
In the definition if says F = C^2/(Nm^2) and I believe it should be F = C^2/(Nm) Yes! The units of F = C^2/(Nm^2) is INCORRECT. It should be F = C^2/(Nm). —Preceding unsigned comment added by 72.33.56.74 ( talk) 20:31, 7 July 2010 (UTC) The definition is 'F=C^2/(Nm) I am unable to see where it is defined at C^2/(Nm^2)? —Preceding unsigned comment added by Rickysz ( talk • contribs) 14:27, 29 July 2010 (UTC)
I'm not sure that the relation to Voltage and Joules is stated correctly. Unless I missed something, F = J / (V^2) rearranges into J = F * (V^2) if you're trying to solve for J. However, many sources ( http://www.ebroadcast.com.au/lookup/encyclopedia/ca/Capacitors.html ) give this formula as J = (F/2) * (V^2). 60.242.28.67 ( talk) 08:01, 15 February 2011 (UTC)
I agree. A number of the equivalences are wrong on this page. J = 1/2 * F * V^2, at the very least, which rearranges into F = 2 * J / V^2 Jonathan ( talk) 13:53, 24 September 2011 (UTC)
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in everyday calculations the W.h is more common than J[oule]. battery charges are often expressed in A.h, caculatively, the Farad also can be said in S[iemens].h, and Henry in Ω.h; (and Wb as V.h) so what prohibits this?
Tabascofernandez (
talk)
00:04, 15 July 2017 (UTC)
In Wikipedia article "Farad", the character "C" is used for the Electric charge. In the article "Capacitance", the same character "C" is used for Capacitance. This is confusing.
Regards, Boris Spasov (bspasov@yahoo.com). — Preceding unsigned comment added by 107.184.14.103 ( talk) 05:46, 24 June 2018 (UTC)
What about redirecting " femtofarad" to "farad"? Or creating a proper article? -- Edcolins 20:48, August 21, 2005 (UTC)
the SI multiples table is ridiculously unnecessary. Do I have to explain why? Fresheneesz 01:08, 23 May 2006 (UTC)
I changed
I hope this is more understandable. (But I would prefer a cited definition from a good source). -- 76.209.28.72 18:51, 26 June 2007 (UTC)
The article " Farad" was created on 8-September-2002 by long-term user Heron. - Wikid77 ( talk) 05:04, 17 September 2008 (UTC)